reverse_linked_list

  • 2022-12-14
  • 浏览 (378)

reverse_linked_list.py 源码

from typing import List


class ListNode:
    def __init__(self, x):
        self.val = x
        self.next = None

class Solution:

    # 迭代
    def reverseList1(self, head: ListNode) -> ListNode:
        prev, back = None, head
        while back:
            back.next, prev, back = prev, back, back.next
        return prev

    # 递归
    def reverseList2(self, head: ListNode) -> ListNode:
        def helper(prev, cur) -> ListNode:
            if not cur:
                return prev
            n = cur.next
            cur.next = prev
            return helper(cur, n)
        return helper(None, head)

你可能感兴趣的文章

add_two_numbers

delete_nth_node

intersection_of_two_linked_lists

0  赞