score_of_parentheses
score_of_parentheses.py 源码
# 括号的分数
class Solution(object):
def scoreOfParentheses_1(self, S):
stack = [0]
for val in S:
if val == '(':
stack.append(0)
else:
v = stack.pop()
stack[-1] += max(2 * v, 1)
return stack.pop()
def scoreOfParentheses_2(self, S):
stack = []
for val in S:
if val == '(':
stack.append(val)
else:
k = 0
while stack[-1] != '(':
k += stack[-1]
stack = stack[:-1]
stack[-1] = 1 if k == 0 else 2 * k
return sum(stack)
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